The time in which Rs. 6000 amounts to Rs. 7986 at 10% p.a. compounded annually is
Given:
Principal \( (P)=6000 \)
Amount $=Rs.\ 7986$
Rate \( (\mathrm{R})=10 \) per annum compounded annually.
To do:
We have to calculate the time.
Solution:
Let the time be $n$.
We know that,
Amount \( (\mathrm{A})=\mathrm{P}\left(1+\frac{R}{100}\right)^{n} \)
Therefore,
$7986=6000(1+\frac{10}{100})^{n}$
$7986 =6000(1+0.1)^n$
$\frac{7986}{6000}=(1.1)^n$
$1.331=(1.1)^n$
$(1.1)^3=(1.1)^n$
Comparing both sides, we get,
$n=3$
Therefore, in 3 years Rs. 6000 amounts to Rs. 7986 at 10% p.a. compounded annually.
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