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The circumference of the base of a circular cylinder is $8\pi\ cm$. The height of cylinder is same as the diameter of the base. How much water can the cylinder hold?
Given: The circumference of the base of a circular cylinder is $8\pi\ cm$. The height of cylinder is same as the diameter of the base.
To do: To find that how much water can the cylinder hold?
Solution:
As given, circumference of the base of the cylinder$=2\pi r=8\pi$
$\Rightarrow r=\frac{8\pi}{2\pi}$
$\Rightarrow r=4$
Also given, The height of cylinder is same as the diameter of the base.
$\Rightarrow h=2r=2\times4=8$
Volume of cylinder$=\pi r^2h$
$=\pi\times4\times4\times8$
$=128\pi\ unit^3$
Thus, the amount of water that cylinder can hold is $128\pi\ unit^3$.
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