The curved surface area of a right circular cylinder of height $ 14 \mathrm{~cm} $ is $ 88 \mathrm{~cm}^{2} $. Find the diameter of the base of the cylinder.

Given :

The curved surface area of a right circular cylinder of height $14\ cm$ is $88\ cm^2$.

To find:

we have to find the diameter of the base of the cylinder.

Solution: 

Let the radius of the base of the cylinder be $r$ cm.

The curved surface area of a cylinder of radius $r$ and height $h = 2\pi rh$ 

Therefore,

$2\pi rh= 2 \times \frac{22}{7} \times r \times 14$

$88 = 88r$

$r=\frac{88}{88}\ m$

$r=1\ m$

Diameter$=2r=2(1)\ m=2\ m$

The diameter of the base of the cylinder is $2\ m$.

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Updated on: 10-Oct-2022

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