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Solve the following expression
$(-21) \times [(-4) + (-6)] = [(-21) \times (-4) + (-21) \times (-6)]$
Given: $(-21) \times [(-4) + (-6)] = [(-21) \times (-4) + (-21) \times (-6)]$
To find: Solve the expression.
Solution:
a (b + c) = a b + a c
L H S :
$ (-21) \times [(-4) + (-6)] = (-21) \times [-4-6]$
= $(-21) \times (-10)$
$(-21) \times [(-4) + (-6)] = 210$
R H S :
$[(-21) \times (-4) + (-21) \times (-6)] = -21 \times -4 + -21 \times -6$
$-21 \times -4 = 84 ; -21 \times -6 = 126$
$ [(-21) \times (-4) + (-21) \times (-6)] = 84 + 126$
$[(-21) \times (-4) + (-21) \times (-6)] = 210$
Therfore, L H S = R H S
$(-21) \times [(-4) + (-6)] = [(-21) \times (-4) + (-21) \times (-6)]$
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