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In the figure below, $ A B C D $ is a square with side $ 2 \sqrt{2} \mathrm{~cm} $ and inscribed in a circle. Find the area of the shaded region. (Use $ \pi=3.14) $"
Given:
\( A B C D \) is a square with side \( 2 \sqrt{2} \mathrm{~cm} \) and inscribed in a circle.
To do:
We have to find the area of the shaded region.
Solution:
From the figure,
$ABCD$ is a square.
$AD = 2\sqrt2\ cm$
Join $AC$,
This implies,
Diagonal of the square $\mathrm{AC}=\sqrt{2} \times \mathrm{AD}$
$=\sqrt{2} \times 2\sqrt{2} \mathrm{~cm}$
$=2 \times 2$
$=4 \mathrm{~cm}$
Diagonal of the square $=$ Diameter of the circle
This implies,
Radius of the circle $=\frac{4}{2}$
$=2 \mathrm{~cm}$
Therefore,
Area of the shaded region $=$ Area of circle $-$ Area of square
$=\pi r^{2}-(\mathrm{AD})^{2}$
$=3.14 \times(2)^{2}-(2\sqrt{2})^{2}$
$=3.14 \times 4-4\times2$
$=4(3.14-2)$
$=4 \times 1.14$
$=4.56 \mathrm{~cm}^{2}$
The area of the shaded region is $4.56\ cm^2$.