In an A.P, if $d=7$, what is the value of $t_{17}−t_2=?$

Given: In an A.P, if $d=7$.

To do: To find the value of $t_{17}-t_2$.

Solution:

Here given, common difference $d=7$

As known,

$n^{th}$ term $t_n=a+( n-1)d$

$\Rightarrow t_{17}=a+( 17-1)d=a+16d$

Similarly,

$t_2=a+( 2-1)d=a+d$

$\therefore t_{17}-t_2$

$=a+16d-a-d$

$=15d$

$=15\times7$

$=105$

Hence, $t_{17}-t_2=105$

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Updated on: 10-Oct-2022

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