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$\frac{-7}{8}$ Compared By $\frac{14}{-16}$ Rational Numbers
To do: $\frac{-7}{8}$ Compared By $\frac{14}{-16}$ Rational Numbers
Solution:
Rational number$\frac{-7}{8}$ is in its lowest or simplest form.
Rational number $\frac{14}{-16}$ is NOT in its lowest or simplest form.
So simplifying $\frac{14}{-16}$ = $\frac{7\times2}{-8\times2}$ = $\frac{7}{-8}$ = $\frac{-7}{8}$
So $\frac{14}{-16}$is same as $\frac{7}{-8}$
So the comparison is that these two rational numbers are equal.
$\frac{-7}{8}$ =$\frac{14}{-16}$
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