Find the value of each of the following:(i) $312+(-165)+(-35)$(ii) $1318+(-385)+(-215)+500$

Given :

The given terms are (i) $312+(-165)+(-35)$ and  (ii) $1318+(-385)+(-215)+500$

To do :

We have to find the values of the given terms.

Solution :

We know that,

$(+) \times (-) = (-)$

Therefore,

(i)$312+(-165)+(-35) = 312-(165)-(35)$

                                $= 312-(165+35)$

                                $= 312-200$

                                $= 112$.

Therefore, the value of $312+(-165)+(-35)$ is 112.

(ii) $1318+(-385)+(-215)+500 = 1318-(385)-(215)+500$

                                               $= 1318+500-(385+215)$

                                               $= 1318+500-600$

                                               $= 1818-600$

                                               $= 1218$

Therefore, the value of  $1318+(-385)+(-215)+500$ is 1218.

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Updated on: 10-Oct-2022

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