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Find the median of the following data.
83, 37, 70, 29, 45, 63, 41, 70, 34, 54
Given:
83, 37, 70, 29, 45, 63, 41, 70, 34, 54
To do:
We have to find the median of the given data.
Solution:
We know that,
Median $= \frac{1}{2}[\frac{n}{2}th\ term+(\frac{n}{2}+1)th\ term]$ (when $n$ is even)
Arranging the given data in ascending order, we get,
$29, 34, 37, 41, 45, 54, 63, 70, 70, 83$
Here,
$n = 10$ which is even
Therefore,
Median $= \frac{1}{2}[5th\ term + 6th\ term]$
$= \frac{1}{2}(45+54)$
$= \frac{99}{2}$
$= 49.5$
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