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A man is instructed to carry a package from the base camp at $B$ to summit $A$ of a hill at a height of $1200\ metres$. The man weighs $800\ N$ and the package weighs $200\ N$. If $g=10\ m/s^2$,(i) how much work does man do against gravity? (ii) what is the potential energy of the package at A if it is assumed to be zero at B
(i) To calculate the work done
Total Wight $=800\ N+200\ N$
Total Weight $=1000\ N$
We know the formula for Work Done
Where,
Vertical displacement $(height)=h=1200\ N$
Force$=mg=1000$
Put Values
Work done $=1200\times1000$
Or Work done $=1200000$
Therefore, work Done is $12\times10^5\ J$
(ii) Potential Energy of package.
We have the formula for Potential Energy
Here we will take only the weight of Package
Weight of Package$=mg=200\ N$
Put these values into $W=mgh$
$P.E=200\times1200$
Or $P.E=240000$
Therefore, Potential Energy is $2,40,000\ J$.
Updated on: 10-Oct-2022
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