The area of a square field is $60025\ m^2$. A man cycle along its boundary at 18 km/hr. In how much time will be return at the starting point.

Given:

The area of a square field is $60025\ m^2$. A man cycle along its boundary at 18 km/hr. 

To do:

We have to find the time in which he will return to the starting point.

Solution:

Area of the square field $= 60025\ m^2$

This implies,

Side of the square field $=\sqrt{60025} \mathrm{~m}$

$=245 \mathrm{~m}$

Perimeter of the square $=4 \times 245 \mathrm{~m}$

$=980 \mathrm{~m}$

Speed of the man $=18 \mathrm{~km} / \mathrm{hr}$

$=18000 \mathrm{~m} / \mathrm{hr}$

Therefore,

Time taken to return $=\frac{980 \times 1}{18000} \mathrm{hr}$

$=\frac{980 \times 1 \times 60}{18000}$ minutes

$=3 \frac{4}{15}$ minutes

$=3$ minutes 16 seconds

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Updated on: 10-Oct-2022

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