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# A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. Calculate the total distance covered.

**Given :**

A car moves with a speed of 40km/h for 15 minutes and then with a speed of 60 Km/h for the next 15 minutes.

**To find :**

We have to find the total distance traveled.

**Solution : **

Let the first part of the distance be x and the second part of the distance be y.

We know that,

$Speed = \frac{Distance}{Time}$

Speed for the first part of the distance $= $40 km/hr

Time taken for the first part of the distance $=$ 15 minutes $= \frac{15}{60}$ hr $= \frac{1}{4}$ hr $= 0.25$ hr

First part of the distance $= speed \times time = 40 \times 0.25 km = 10 km$

Speed for the second part of the distance $=$ 60 km/hr

Time taken for the first part of the distance $=$ 15 minutes $= \frac{15}{60} hr = \frac{1}{4} hr = 0.25 hr$

Second part of the distance $= speed \times time = 60 \times 0.25 km = 15 km$

**Therefore, the total distance covered is $(10+15) km = 25 km$.**