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A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. Calculate the total distance covered.
Given :
A car moves with a speed of 40km/h for 15 minutes and then with a speed of 60 Km/h for the next 15 minutes.
To find :
We have to find the total distance traveled.
Solution :
Let the first part of the distance be x and the second part of the distance be y.
We know that,
$Speed = \frac{Distance}{Time}$
Speed for the first part of the distance $= $40 km/hr
Time taken for the first part of the distance $=$ 15 minutes $= \frac{15}{60}$ hr $= \frac{1}{4}$ hr $= 0.25$ hr
First part of the distance $= speed \times time = 40 \times 0.25 km = 10 km$
Speed for the second part of the distance $=$ 60 km/hr
Time taken for the first part of the distance $=$ 15 minutes $= \frac{15}{60} hr = \frac{1}{4} hr = 0.25 hr$
Second part of the distance $= speed \times time = 60 \times 0.25 km = 15 km$
Therefore, the total distance covered is $(10+15) km = 25 km$.