Number of Digits in a^b in C++

C++Server Side ProgrammingProgramming

The power of a number can be computed using the iterative multiplication or function that the language provides. It's a straightforward thing.

Here, we have to find the a raised to power b. And the number of digits in the result. Let's see some examples.

Input

a = 5
b = 2

Output

2

Input

a = 7
b = 6

Output

6

Algorithm

  • Initialise the number a and b.
  • Find the value of ab.
  • The ceil of log10(n) will give you number of digits in the number n.
  • Find it and return it.

Implementation

Following is the implementation of the above algorithm in C++

#include <bits/stdc++.h>
using namespace std;
int getDigitsCount(int a, int b) {
   return ceil(log10(pow(a, b)));
}
int main() {
   int a = 8;
   int b = 3;
   cout << getDigitsCount(a, b) << endl;
   return 0;
}

Output

If you run the above code, then you will get the following result.

3
raja
Updated on 26-Oct-2021 06:53:53

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