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MySQL query to perform sort order on same field
For this, use ORDER BY IF().
Let us first create a table −
mysql> create table DemoTable801 ( Score int ); Query OK, 0 rows affected (0.69 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable801 values(30); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable801 values(99); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable801 values(45); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable801 values(55); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable801 values(99); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable801 values(69); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable801 values(25); Query OK, 1 row affected (0.20 sec) mysql> insert into DemoTable801 values(79); Query OK, 1 row affected (0.12 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable801;
This will produce the following output -
+-------+ | Score | +-------+ | 30 | | 99 | | 45 | | 55 | | 99 | | 69 | | 25 | | 79 | +-------+ 8 rows in set (0.00 sec)
Following is the query to perform sort order on same field −
mysql> select *from DemoTable801 order by if(Score=99,1,0), Score;
This will produce the following output -
+-------+ | Score | +-------+ | 25 | | 30 | | 45 | | 55 | | 69 | | 79 | | 99 | | 99 | +-------+ 8 rows in set (0.00 sec)
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