MySQL- GROUP and COUNT by date?

You can use GROUP BY clause and COUNT() function for this. The syntax is as follows −

SELECT yourColumnName1,yourColumnName2,..N,COUNT(*) as anyAliasName FROM yourTableName
GROUP BY yourColumnName1,yourColumnName2;

To understand the above syntax, let us create a table. The query to create a table is as follows −

mysql> create table GroupAndCountByDate
   -> (
   -> Id int NOT NULL AUTO_INCREMENT,
   -> TripDate date,
   -> ShopId int,
   -> PRIMARY KEY(Id)
   -> );
Query OK, 0 rows affected (0.79 sec)

Now you can insert some records in the table using insert command. The query is as follows −

mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-01-31',10);
Query OK, 1 row affected (0.52 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-02-01',15);
Query OK, 1 row affected (0.17 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-01-31',10);
Query OK, 1 row affected (0.23 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-02-01',15);
Query OK, 1 row affected (0.31 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-03-23',20);
Query OK, 1 row affected (0.15 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-04-21',25);
Query OK, 1 row affected (0.20 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-03-13',20);
Query OK, 1 row affected (0.16 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-04-06',25);
Query OK, 1 row affected (0.17 sec)

Display all records from the table using select statement. The query is as follows −

mysql> select *from GroupAndCountByDate;

The following is the output −

+----+------------+--------+
| Id | TripDate   | ShopId |
+----+------------+--------+
|  1 | 2019-01-31 |     10 |
|  2 | 2019-02-01 |     15 |
|  3 | 2019-01-31 |     10 |
|  4 | 2019-02-01 |     15 |
|  5 | 2019-03-23 |     20 |
|  6 | 2019-04-21 |     25 |
|  7 | 2019-03-13 |     20 |
|  8 | 2019-04-06 |     25 |
+----+------------+--------+
8 rows in set (0.00 sec)

Here is the query to GROUP and count by date −

mysql> select TripDate,ShopId,COUNT(*) as TOTALTRIP
   -> from GroupAndCountByDate
   -> group by TripDate,ShopId;

The following is the output −

+------------+--------+-----------+
| TripDate   | ShopId | TOTALTRIP |
+------------+--------+-----------+
| 2019-01-31 |      10 |        2 |
| 2019-02-01 |      15 |        2 |
| 2019-03-23 |      20 |        1 |
| 2019-04-21 |      25 |        1 |
| 2019-03-13 |      20 |        1 |
| 2019-04-06 |      25 |        1 |
+------------+--------+-----------+
6 rows in set (0.00 sec)