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Get first date from timestamp in MySQL group by another column with duplicate value
For this, you can use aggregate function MIN() and GROUP BY. Let us first create a table −
mysql> create table DemoTable1870 ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, Value int, ShippingTimestamp varchar(100) ); Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1870(Value,ShippingTimestamp) values(10,'1570645800'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1870(Value,ShippingTimestamp) values(10,'1546194600'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1870(Value,ShippingTimestamp) values(11,'1573324200'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1870(Value,ShippingTimestamp) values(11,'1557599400'); Query OK, 1 row affected (0.00 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable1870;
This will produce the following output −
+----+-------+-------------------+ | Id | Value | ShippingTimestamp | +----+-------+-------------------+ | 1 | 10 | 1570645800 | | 2 | 10 | 1546194600 | | 3 | 11 | 1573324200 | | 4 | 11 | 1557599400 | +----+-------+-------------------+ 4 rows in set (0.00 sec)
Here is the query to get first date from timestamp in MySQL &Minus;
mysql> select min(ShippingTimestamp) from DemoTable1870 group by Value;
This will produce the following output −
+------------------------+ | min(ShippingTimestamp) | +------------------------+ | 1546194600 | | 1557599400 | +------------------------+ 2 rows in set (0.00 sec)
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