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Multi-catch in Java
An exception is an issue (run time error) that occurred during the execution of a program. When an exception occurred the program gets terminated abruptly and, the code past the line that generated the exception never gets executed.
Multiple exceptions in a code
Before Java 7 whenever we have a code that may generate more than one exception and if you need to handle them specifically you are supposed to use multiple catch blocks on a single try.
Multicatch block
From Java 7 onwards a Multi-catch block is introduced using this, you can handle more than one exception within a single catch block.
In this, you need to specify all the exception classes to be handled separated by “ | ” as shown below −
catch(ArrayIndexOutOfBoundsException | ArithmeticException exp) { System.out.println("Warning: Enter inputs as per instructions "); }
Example
The following Java program demonstrates the usage of Multi-catch. Here we are handling all the exceptions in a single catch block.
import java.util.Arrays; import java.util.Scanner; public class MultiCatch { public static void main(String [] args) { Scanner sc = new Scanner(System.in); int[] arr = {10, 20, 30, 2, 0, 8}; System.out.println("Array: "+Arrays.toString(arr)); System.out.println("Choose numerator and denominator(not 0) from this array, (enter positions 0 to 5)"); int a = sc.nextInt(); int b = sc.nextInt(); try { int result = (arr[a])/(arr[b]); System.out.println("Result of "+arr[a]+"/"+arr[b]+": "+result); } catch(ArrayIndexOutOfBoundsException | ArithmeticException exp) { System.out.println("Warning: Enter inputs as per instructions "); } } }
Output1
Enter 3 integer values one by one: Array: [10, 20, 30, 2, 0, 8] Choose numerator and denominator (not 0) from this array, (enter positions 0 to 5) 0 9 Warning: Enter inputs as per instructions
Output2
Enter 3 integer values one by one: Array: [10, 20, 30, 2, 0, 8] Choose numerator and denominator (not 0) from this array, (enter positions 0 to 5) 2 4 Warning: Enter inputs as per instructions
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