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Minimum number of elements to add to make median equals x using C++.
Problem statement
Given an array “arr” of size n and element x, the task is to find a minimum number of elements to be added in array to make median equals x.
A median in an array with the length of n is an element which occupies position number (n-1)/2 after we sort the elements in the non-decreasing order. For example, in below array median is 20 −
arr1[] = {10, 20, 30, 40}
If arr[] = {1, 2, 3} and x = 4 then we have to add 4 number i.e. {4, 5, 5, 5} in array to make median equal to 4
Algorithm
The algorithm is very simple. We have to add one number x to the array until the median of the array equals to x
Example
#include <iostream>
#include <algorithm>
using namespace std;
int minNumbersToBeAdded(int *arr, int n, int x){
sort(arr, arr + n);
int cnt = 0;
while (arr[(n - 1)/2] != x) {
arr[n] = x;
++n;
sort(arr, arr + n);
++cnt;
}
return cnt;
}
int main(){
int arr[20] = {1, 2, 3};
int x = 4;
int n = 3;
cout << "Minimum numbers to be added = " << minNumbersToBeAdded(arr, n, x) << endl;
return 0;
}Output
When you compile and execute the above program. It generates the following output −
Minimum numbers to be added = 4
Updated on: 31-Oct-2019
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