# Maximum of sum and product of digits until number is reduced to a single digit in C++

C++Server Side ProgrammingProgramming

In this tutorial, we will be discussing a program to find maximum of sum and product of digits until number is reduced to a single digit

For this we will be provided with a random number. Our task is to find and print out the maximum of sum and product of the digits of the given number until it coverts to a single digit

## Example

Live Demo

#include<bits/stdc++.h>
using namespace std;
//converting number to single digit by adding
long repeatedSum(long n) {
if (n == 0)
return 0;
return (n % 9 == 0) ? 9 : (n % 9);
}
//converting number to single digit by multiplying
long repeatedProduct(long n) {
long prod = 1;
while (n > 0 || prod > 9) {
if (n == 0) {
n = prod;
prod = 1;
}
prod *= n % 10;
n /= 10;
}
return prod;
}
//finding maximum
long maxSumProduct(long N) {
if (N < 10)
return N;
return max(repeatedSum(N), repeatedProduct(N));
}
int main() {
long n = 631;
cout << maxSumProduct(n)<<endl;
return 0;
}

## Output

8