# C Program to sum the digits of a given number in single statement

C++Server Side ProgrammingProgramming

In this section we will see how to find the sum of digits without writing multiple statements. In other words, we will find the sum of digits in a single statement.

As we know that, to find the sum of digits we cut the last digit by taking the remainder after dividing the number by 10, and then divide the number by 10 again and again until the number becomes 0.

To do these task in a single statement the for loop can be used. As we know there are three different sections in the for loop. In the initialization phase we are doing nothing in this case, then in the condition checking phase are checking whether the number is greater than 0 or not. In the increment decrement phase, we are doing multiple tasks. At first we are incrementing the sum by taking the last digits of the number, and also reduce the number by dividing it by 10.

## Example Code

#include<stdio.h>
main() {
int n, sum = 0;
printf("Enter a number: "); //take the number from the user
scanf("%d", &n);
for(; n > 0; sum += n%10, n/= 10) {
}
printf("The sum of digits: %d", sum);
}

## Output 1

Enter a number: 457
The sum of digits: 16
Updated on 30-Jul-2019 22:30:25