Maximum Number of Vowels in a Substring of Given Length in C++

C++Server Side ProgrammingProgramming

C in Depth: The Complete C Programming Guide for Beginners

45 Lectures 4.5 hours

Practical C++: Learn C++ Basics Step by Step

Most Popular

50 Lectures 4.5 hours

Master C and Embedded C Programming- Learn as you go

Best Seller

66 Lectures 5.5 hours

Suppose we have a string s and an integer k. We have to find the maximum number of vowel letters in any substring of s with length k.

So, if the input is like s = "abciiidef", k = 3, then the output will be 3

To solve this, we will follow these steps −

• cnt := 0

• Define one set m

• for each vowel v, do

• insert v into m

• ret := 0

• for initialize i := 0, when i < k, update (increase i by 1), do −

• cnt := cnt + (1 when s[i] is in m, otherwise 0)

• ret := maximum of ret and cnt

• n := size of s

• for initialize i := k, when i < n, update (increase i by 1), do −

• if s[i - k] is member of m, then −

• (decrease cnt by 1)

• cnt := cnt + (1 when s[i] is in m, otherwise 0)

• ret := maximum of ret and cnt

• return ret

Example

Let us see the following implementation to get a better understanding −

Live Demo

#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
int maxVowels(string s, int k) {
int cnt = 0;
set<char> m;
for (auto it : { 'a', 'e', 'i', 'o', 'u' })
m.insert(it);
int ret = 0;
for (int i = 0; i < k; i++) {
cnt += m.count(s[i]) ? 1 : 0;
}
ret = max(ret, cnt);
int n = s.size();
for (int i = k; i < n; i++) {
if (m.count(s[i - k])) {
cnt--;
}
cnt += m.count(s[i]) ? 1 : 0;
ret = max(ret, cnt);
}
return ret;
}
};
main(){
Solution ob;
cout << (ob.maxVowels("abciiidef",3));
}

Input

"abciiidef",3

Output

3
Updated on 17-Nov-2020 12:35:02