# Maximum number of people that can be killed with strength P in C++

Given the task is to find the maximum number of people that can be killed with strength P. Consider a row with infinite people and each of them have an index number starting from 1.

The strength of the sth person is represented by s2. After killing a person with s strength your strength also decreases by s.

Let’s now understand what we have to do using an example −

## Input

P = 20

## Output

3

## Explanation

Strength of 1st person = 1 * 1 = 1 < 20, therefore 1st person can be killed.
Remaining strength = P – 1 = 20 – 1 = 19
Strength of 2nd person = 2 * 2 = 4 < 19, therefore 2nd person can be killed.
Remaining strength = P – 4 = 19 – 4 = 15
Strength of 3rd person = 3 * 3 = 9 < 15, therefore 3rd person can be killed.
Remaining strength = P – 9 = 15 – 9 = 6
Strength of 4th person = 4 * 4 = 16 > 6, therefore 4th person cannot be killed.
Output = 3

## Input

30

## Output

4

## Approach used in the below program as follows

• In main() function initialize P = 30 of type int as it will store the strength and pass it into Max() function.

• In Max() function initialize s = 0 and P = 0 both of type int.

• Loop from j = 1 till j * j <= P

• Put s = s + (j * j) and if s <= P add 1 to ans, else break;

• Return ans.

## Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
int Max(int P){
int s = 0, ans = 0;
for (int j = 1; j * j <= P; j++){
s = s + (j * j);
if (s <= P)
ans++;
else
break;
}
return ans;
}
//main function
int main(){
//Strength
int P = 30;
cout << “Maximum number of people that can be killed with strength P are: ”<<Max(P);
return 0;
}

## Output

Maximum number of people that can be killed with strength P are: 4

Updated on: 03-Aug-2020

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