LocalTime isAfter() method in Java

Java 8Object Oriented ProgrammingProgramming

It can be checked if a particular LocalTime is after the other LocalTime in a timeline using the isAfter() method in the LocalTime class in Java. This method requires a single parameter i.e. the LocalTime object that is to be compared. It returns true if the LocalTime object is after the other LocalTime object and false otherwise.

A program that demonstrates this is given as follows

Example

 Live Demo

import java.time.*;
public class Main {
   public static void main(String[] args) {
      LocalTime lt1 = LocalTime.parse("11:37:12");
      LocalTime lt2 = LocalTime.parse("23:15:30");
      System.out.println("The LocalTime lt1 is: " + lt1);
      System.out.println("The LocalTime lt2 is: " + lt2);
      boolean flag = lt1.isAfter(lt2);
      if(flag)
         System.out.println("\nLocalTime object lt1 is after LocalTime object lt2");
      else
         System.out.println("\nLocalTime object lt1 is before LocalTime object lt2");
   }
}

output

The LocalTime lt1 is: 11:37:12
The LocalTime lt2 is: 23:15:30
LocalTime object lt1 is before LocalTime object lt2

Now let us understand the above program.

The two LocalTime objects lt1 and lt2 are displayed. It is checked if the LocalTime object lt1 is after the LocalTime object lt2 in the timeline using the isAfter() method. The returned value is displayed using an if statement. A code snippet that demonstrates this is as follows:

LocalTime lt1 = LocalTime.parse("11:37:12");
LocalTime lt2 = LocalTime.parse("23:15:30");
System.out.println("The LocalTime lt1 is: " + lt1);
System.out.println("The LocalTime lt2 is: " + lt2);
boolean flag = lt1.isAfter(lt2);
if(flag)
   System.out.println("\nLocalTime object lt1 is after LocalTime object lt2");
else
   System.out.println("\nLocalTime object lt1 is before LocalTime object lt2");
raja
Published on 26-Mar-2019 13:57:06
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