List consisting of all the alternate elements in Python

In this article, we are going to learn how to get alternate elements from the list. We'll see two different ways to solve the problem.

Follow the below steps to solve the problem in one way.

• Initialize the list.
• 3Iterate over the list and store all the elements from the odd index.
• Print the result.

Example

Let's see the code.

 Live Demo

# Initializing the list
numbers = [1, 2, 3, 4, 5]

# finding alternate elements
result = [numbers[i] for i in range(len(numbers)) if i % 2 != 0]

# printing the result
print(result)

If you run the above code, then you will get the following result.

[2, 4]

We'll get all the odd positioned elements using slicing. Follow the below steps to solve the problem.

• Initialize the list.
• Get element which are in odd index using [1::2] slicing.
• Print the result.

Example

Let's see the code.

 Live Demo

# Initializing the list
numbers = [1, 2, 3, 4, 5]

# finding alternate elements
result = numbers[1::2]

# printing the result
print(result)

If you run the above code, then you will get the following result.

Output

[2, 4]

Conclusion

If you have any queries in the article, mention them in the comment section.

Hafeezul Kareem

Published on 13-Nov-2020 18:16:46

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