Largest number smaller than or equal to N divisible by K in C++

C++Server Side ProgrammingProgramming

In this tutorial, we are going to write a program that finds the number that is smaller than or equal to N and divisible by k.

Let's see the steps to solve the problem.

  • Initialise the numbers n and k.
  • Find the remainder with modulo operator.
  • If the remainder is zero, then return n.
  • Else return n - remainder.

Example

Let's see the code.

 Live Demo

#include <bits/stdc++.h>
using namespace std;
int findLargerNumber(int n, int k) {
   int remainder = n % k;
   if (remainder == 0) {
      return n;
   }
   return n - remainder;
}
int main() {
   int n = 33, k = 5;
   cout << findLargerNumber(n, k) << endl;
   return 0;
}

Output

If you run the above code, then you will get the following result.

30

Conclusion

If you have any queries in the tutorial, mention them in the comment section.

raja
Published on 09-Apr-2021 13:38:38
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