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# Largest number smaller than or equal to N divisible by K in C++

In this tutorial, we are going to write a program that finds the number that is smaller than or equal to N and divisible by k.

Let's see the steps to solve the problem.

- Initialise the numbers n and k.
- Find the remainder with modulo operator.
- If the remainder is zero, then return n.
- Else return n - remainder.

## Example

Let's see the code.

#include <bits/stdc++.h> using namespace std; int findLargerNumber(int n, int k) { int remainder = n % k; if (remainder == 0) { return n; } return n - remainder; } int main() { int n = 33, k = 5; cout << findLargerNumber(n, k) << endl; return 0; }

## Output

If you run the above code, then you will get the following result.

30

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

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