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# Largest set with bitwise OR equal to n in C++

In this tutorial, we are going to write a program that finds the largest set with bitwise OR is equal to the given number n.

Let's see the steps to solve the problem.

- Initialise the number n.
- Write a loop that iterates from 0 to n.
- If the i | n is equal to n, then add i to the result.

- Return the result.

## Example

Let's see the code.

#include <bits/stdc++.h> using namespace std; void printBitWiseOrSet(int n) { vector<int> v; for (int i = 0; i <= n; i++) { if ((i | n) == n) { v.push_back(i); } } for (int i = 0; i < v.size(); i++) { cout << v[i] << ' '; } cout << endl; } int main() { int n = 7; printBitWiseOrSet(n); return 0; }

## Output

If you run the above code, then you will get the following result.

0 1 2 3 4 5 6 7

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

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