# Largest Number By Two Times in Python

PythonServer Side ProgrammingProgramming

Suppose we have a list of numbers; we have to check whether the largest number is bigger than the second-largest number by more than two times. As an example, if the list is like [3, 9, 6], then it will return false, as 9 is not bigger than 12 (2 times 6). When the list is [6, 3, 15], it will return true, as 15 is bigger than 12 (2 times 6).

To solve this, we will follow these steps −

• if size of nums < 2, then
• return False
• p_max := minimum of nums and nums
• c_max := maximum of nums and nums
• for i in range 2 to size of nums, do
• if nums[i] > p_max, then
• if nums[i] > c_max, then
• p_max := c_max
• c_max := nums[i]
• otherwise,
• p_max := nums[i]
• return c_max > p_max * 2

Let us see the following implementation to get better understanding −

## Example

Live Demo

class Solution:
def solve(self, nums):
if len(nums) < 2:
return False
p_max = min(nums, nums)
c_max = max(nums, nums)
for i in range(2, len(nums)):
if nums[i] > p_max:
if nums[i] > c_max:
p_max = c_max
c_max = nums[i]
else:
p_max = nums[i]
return c_max > p_max * 2
ob = Solution()
nums = [3,6,15]
print(ob.solve(nums))

## Input

[3,6,15]

## Output

None