JSON.simple - Escaping Special Characters

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The following characters are reserved characters and can not be used in JSON and must be properly escaped to be used in strings.

• Backspace to be replaced with \b

• Form feed to be replaced with \f

• Newline to be replaced with \n

• Carriage return to be replaced with \r

• Tab to be replaced with \t

• Double quote to be replaced with \"

• Backslash to be replaced with \\

JSONObject.escape() method can be used to escape such reserved keywords in a JSON String. Following is the example −

Example

import org.json.simple.JSONObject;

public class JsonDemo {
   public static void main(String[] args) {
      JSONObject jsonObject = new JSONObject();
      String text = "Text with special character /\"\'\b\f\t\r\n.";
      System.out.println(text);
      System.out.println("After escaping.");
      text = jsonObject.escape(text);
      System.out.println(text);
   }
}

Output

Text with special character /"'
.
After escaping.
Text with special character \/\"'\b\f\t\r\n.