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Join Tuples if similar initial element in Python
When it is required to join tuples if they contain a similar initial element, a simple ‘for’ loop and an ‘of’ condition can be used. To store elements to one list, the ‘extend’ method can be used.
Below is the demonstration of the same −
Example
my_list = [(43, 15), (66, 98), (64, 80), (14, 9), (47, 17)]
print("The list is : ")
print(my_list)
my_result = []
for sub in my_list:
if my_result and my_result[-1][0] == sub[0]:
my_result[-1].extend(sub[1:])
else:
my_result.append([ele for ele in sub])
my_result = list(map(tuple, my_result))
print("The extracted elements are : " )
print(my_result)Output
The list is : [(43, 15), (66, 98), (64, 80), (14, 9), (47, 17)] The extracted elements are : [(43, 15), (66, 98), (64, 80), (14, 9), (47, 17)]
Explanation
A list of tuple is defined, and is displayed on the console.
An empty list is defined.
The list of tuple is iterated over, and is checked to see if the initial elements match.
If they match, the element is stored in the empty list.
Otherwise, it is first converted into tuple, and then to a list, and then stored in the empty lit.
This is the output that is displayed on the console.
Updated on: 17-Apr-2021
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