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JavaScript Separate objects based on properties
Suppose, we have an object like this −
const obj = {
0: { "time": 1, "day": 1, },
1: { "time": 2, "day": 1, },
2: { "time": 3, "day": 1, },
3: { "time": 1, "day": 2, },
4: { "time": 2, "day": 2, },
5: { "time": 3, "day": 2, }
};We are required to write a JavaScript function that takes one such object and groups all the key value pairs in separate sub objects that have the same value for the day key.
Output
The output for the above object should be −
const output = { '1':
{ '1': { time: 1, day: 1 },
'2': { time: 2, day: 1 },
'3': { time: 3, day: 1 } },
'2':
{ '1': { time: 1, day: 2 },
'2': { time: 2, day: 2 },
'3': { time: 3, day: 2 } }
}Example
The code for this will be −
const obj = {
0: { "time": 1, "day": 1, },
1: { "time": 2, "day": 1, },
2: { "time": 3, "day": 1, },
3: { "time": 1, "day": 2, },
4: { "time": 2, "day": 2, },
5: { "time": 3, "day": 2, }
};
const groupObject = obj => {
let res = {};
res = Object.values(obj).reduce((acc, val) => {
if(acc[val['day']] === undefined){
acc[val['day']] ={};
};
acc[val['day']][val['time']] = val;
return acc;
},{});
return res;
};
console.log(groupObject(obj));Output
The output in the console −
{
'1': {
'1': { time: 1, day: 1 },
'2': { time: 2, day: 1 },
'3': { time: 3, day: 1 }
},
'2': {
'1': { time: 1, day: 2 },
'2': { time: 2, day: 2 },
'3': { time: 3, day: 2 }
}
}
Updated on: 12-Oct-2020
965 Views
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