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Java Program to subtract integers and check for overflow
To check for Integer overflow, we need to check the Integer.MAX_VALUE with the subtracted integers result, Here, Integer.MAX_VALUE is the maximum value of an integer in Java.
Let us see an example wherein integers are subtracted and if the result is more than Integer.MAX_VALUE, then an exception is thrown.
The following is an example showing how to check for Integer overflow.
Example
public class Demo {
public static void main(String[] args) {
int val1 = 9898999;
int val2 = 8784556;
System.out.println("Value1: "+val1);
System.out.println("Value2: "+val2);
long sub = (long)val1 - (long)val2;
if (sub > Integer.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
// displaying subtraction result
System.out.println("Subtraction Result: "+(int)sub);
}
}Output
Value1: 9898999 Value2: 8784556 Subtraction Result: 1114443
In the above example, we have taken the following two integers −
int val1 = 9898999; int val2 = 8784556;
Now we will cast and subtract them to a long.
long sub = (long)val1 - (long)val2;
If the result is more than the maximum value, then an exception is thrown.
If (sub > Integer.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
Updated on: 26-Jun-2020
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