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Java Program to multiply long integers and check for overflow
To check for Long overflow, we need to check the Long.MAX_VALUE with the multiplied long result, Here, Long.MAX_VALUE is the maximum value of Long type in Java.
Let us see an example wherein long values are multiplied and if the result is more than the Long.MAX_VALUE, then an exception is thrown.
The following is an example showing how to check for Long overflow.
Example
public class Demo {
public static void main(String[] args) {
long val1 = 6999;
long val2 = 67849;
System.out.println("Value1: "+val1);
System.out.println("Value2: "+val2);
long mul = val1 * val2;
if (mul > Long.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
// displaying multiplication
System.out.println("Multiplication Result: "+(long)mul);
}
}Output
Value1: 6999 Value2: 67849 Multiplication Result: 474875151
In the above example, we have taken the following two integers.
long val1 = 6999; long val2 = 67849;
Now we will multiply.
long mul = val1 * val2;
If the result is more than the maximum value, then an exception is thrown.
If (mul > Long.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
Updated on: 26-Jun-2020
1K+ Views
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