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Index Pairs of a String in Python
Suppose we have a text string and words (a list of strings), we have to find all index pairs [i, j] such that the substring text[i]...text[j] is in the list of words. So if the string is like “ababa” and words array is like [“aba”, “ab”], then the output will be [[0,1], [0,2], [2,3], [2,4]]. One thing we can notice, that the matches can overlap, the “aba” is matched in [0,2] and [2,4].
To solve this, we will follow these steps −
- res := an empty list
- for i in range 0 to a length of string
- for j in range i + 1 to length of string + 1
- if substring of string from index i to j in words −
- add (i, j – 1) into the result array
- if substring of string from index i to j in words −
- for j in range i + 1 to length of string + 1
- return result
Example(Python)
Let us see the following implementation to get a better understanding −
class Solution(object):
def indexPairs(self, text, words):
result = []
for i in range(len(text)):
for j in range(i+1,len(text)+1):
if text[i:j] in words:
result.append([i,j-1])
return result
ob1 = Solution()
print(ob1.indexPairs("ababa",["aba","ab"]))Input
"ababa" ["aba","ab"]
Output
[[0,1],[0,2],[2,3],[2,4]]
Updated on: 28-Apr-2020
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