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How to replace NAs with non-NA if there is only one non-NA in R data frame based on another column?
If we have only one non-NA value in an R data frame column and a column that is categorical then we might want to replace the NAs with the given non-NA. For this purpose, we can follow the below steps −
- First of all, creating a data frame
- Then replacing the NA with non-NA with the help of min function of base R and mutate function of dplyr package.
Create the data frame
Let's create a data frame as shown below −
Grp<-rep(LETTERS[1:4],each=5) Response<-rep(c(1,NA,3,NA,5,NA,10,NA),times=c(1,4,1,4,1,4,1,4)) df<-data.frame(Grp,Response) df
On executing, the above script generates the below output(this output will vary on your system due to randomization) −
Grp Response 1 A 1 2 A NA 3 A NA 4 A NA 5 A NA 6 B 3 7 B NA 8 B NA 9 B NA 10 B NA 11 C 5 12 C NA 13 C NA 14 C NA 15 C NA 16 D 10 17 D NA 18 D NA 19 D NA 20 D NA
Replacing NA with Non-NA based on another column
Replacing the NA with non-NA in Response column based on Grp column −
Grp<-rep(LETTERS[1:4],each=5) Response<-rep(c(1,NA,3,NA,5,NA,10,NA),times=c(1,4,1,4,1,4,1,4)) df<-data.frame(Grp,Response) library(dplyr) df%>%group_by(Grp)%>%mutate(Response=min(Response,na.rm=TRUE))
Output
# A tibble: 20 x 2 # Groups: Grp [4] Grp Response <chr> <dbl> 1 A 1 2 A 1 3 A 1 4 A 1 5 A 1 6 B 3 7 B 3 8 B 3 9 B 3 10 B 3 11 C 5 12 C 5 13 C 5 14 C 5 15 C 5 16 D 10 17 D 10 18 D 10 19 D 10 20 D 10
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