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How to reorder the row indices in an R data frame?
If we have a data frame where row indices are not in correct sequence then we can set them to NULL to get the correct sequence of row numbers starting from 1.
For example, if we have a data frame called df which has row ordered in an inappropriate way then we can reorder the row indices in correct order by using the command given below −
row.names(df)<- NULL
Example 1
Following snippet creates a sample data frame −
x<-rnorm(20) y<-rnorm(20) df1<-data.frame(x,y) df1
The following dataframe is created −
x y 1 0.79220702 0.74396588 2 -0.27362051 -0.09125937 3 -1.34248184 -1.42285864 4 -1.10430033 0.26453631 5 -0.52047324 -0.54336532 6 -1.20612600 0.30704459 7 1.62577878 0.58061047 8 -0.09384629 -0.16973222 9 2.83732637 -0.58291919 10 -0.12450580 -0.76230292 11 1.50889524 1.13920262 12 0.19941471 0.81462851 13 0.21843905 -0.49421398 14 -1.97555113 -0.78007517 15 -1.02591803 -0.21299362 16 1.43648115 0.71561607 17 -0.15479259 0.16713844 18 0.06903559 -2.15635528 19 1.51844896 0.49315357 20 0.25861358 -1.43660348
To change the order of row indices in df1, add the following code to the above snippet −
x<-rnorm(20) y<-rnorm(20) df1<-data.frame(x,y) df1<-df1[sample(1:nrow(df1)),] df1
Output
If you execute all the above given snippets as a single program, it generates the following output −
x y 16 1.43648115 0.71561607 6 -1.20612600 0.30704459 3 -1.34248184 -1.42285864 20 0.25861358 -1.43660348 9 2.83732637 -0.58291919 1 0.79220702 0.74396588 8 -0.09384629 -0.16973222 19 1.51844896 0.49315357 2 -0.27362051 -0.09125937 4 -1.10430033 0.26453631 12 0.19941471 0.81462851 13 0.21843905 -0.49421398 18 0.06903559 -2.15635528 10 -0.12450580 -0.76230292 14 -1.97555113 -0.78007517 5 -0.52047324 -0.54336532 11 1.50889524 1.13920262 17 -0.15479259 0.16713844 7 1.62577878 0.58061047 15 -1.02591803 -0.21299362
To reorder the row indices in df1, add the following code to the above snippet −
x<-rnorm(20) y<-rnorm(20) df1<-data.frame(x,y) df1<-df1[sample(1:nrow(df1)),] row.names(df1)<-NULL df1
Output
If you execute all the above given snippets as a single program, it generates the following output −
x y 1 1.43648115 0.71561607 2 -1.20612600 0.30704459 3 -1.34248184 -1.42285864 4 0.25861358 -1.43660348 5 2.83732637 -0.58291919 6 0.79220702 0.74396588 7 -0.09384629 -0.16973222 8 1.51844896 0.49315357 9 -0.27362051 -0.09125937 10 -1.10430033 0.26453631 11 0.19941471 0.81462851 12 0.21843905 -0.49421398 13 0.06903559 -2.15635528 14 -0.12450580 -0.76230292 15 -1.97555113 -0.78007517 16 -0.52047324 -0.54336532 17 1.50889524 1.13920262 18 -0.15479259 0.16713844 19 1.62577878 0.58061047 20 -1.02591803 -0.21299362
Example 2
Following snippet creates a sample data frame −
a<-rpois(20,2) b<-rpois(20,5) c<-rpois(20,2) df2<-data.frame(a,b,c) df2
The following dataframe is created −
a b c 1 2 1 2 2 0 10 0 3 1 2 1 4 2 5 0 5 4 4 2 6 2 4 5 7 3 5 2 8 4 2 3 9 4 6 2 10 1 3 3 11 1 9 1 12 2 4 3 13 4 6 1 14 2 4 1 15 4 7 3 16 1 2 0 17 0 5 1 18 2 4 1 19 0 8 5 20 3 6 3
To change the order of row indices in df2, add the following code to the above snippet −
a<-rpois(20,2) b<-rpois(20,5) c<-rpois(20,2) df2<-data.frame(a,b,c) df2<-df2[sample(1:nrow(df2)),] df2
Output
If you execute all the above given snippets as a single program, it generates the following output −
a b c 6 2 4 5 7 3 5 2 9 4 6 2 15 4 7 3 2 0 10 0 19 0 8 5 10 1 3 3 20 3 6 3 16 1 2 0 3 1 2 1 18 2 4 1 5 4 4 2 12 2 4 3 17 0 5 1 4 2 5 0 8 4 2 3 11 1 9 1 13 4 6 1 1 2 1 2 14 2 4 1
To reorder the row indices in df2, add the following code to the above snippet −
a<-rpois(20,2) b<-rpois(20,5) c<-rpois(20,2) df2<-data.frame(a,b,c) df2<-df2[sample(1:nrow(df2)),] row.names(df2)<-NULL df2
Output
If you execute all the above given snippets as a single program, it generates the following output −
a b c 1 2 4 5 2 3 5 2 3 4 6 2 4 4 7 3 5 0 10 0 6 0 8 5 7 1 3 3 8 3 6 3 9 1 2 0 10 1 2 1 11 2 4 1 12 4 4 2 13 2 4 3 14 0 5 1 15 2 5 0 16 4 2 3 17 1 9 1 18 4 6 1 19 2 1 2 20 2 4 1
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