How to remove rows from data frame in R that contains NaN?

The NaN values are referred to as the Not A Number in R. It is also called undefined or unrepresentable but it belongs to numeric data type for the values that are not numeric, especially in case of floating-point arithmetic. To remove rows from data frame in R that contains NaN, we can use the function na.omit.

Example1

 Live Demo

Consider the below data frame −

x1<−sample(c(NaN,5,10),20,replace=TRUE)
x2<−sample(c(NaN,0,1),20,replace=TRUE)
df1<−data.frame(x1,x2)
df1

Output

x1 x2
1 NaN NaN
2 10 0
3 NaN NaN
4 NaN NaN
5 NaN NaN
6 NaN NaN
7 5 1
8 5 1
9 5 NaN
10 10 NaN
11 5 NaN
12 NaN NaN
13 NaN NaN
14 NaN NaN
15 10 1
16 10 0
17 NaN NaN
18 NaN 1
19 NaN NaN
20 5 1

Removing rows with NaN from df1 −

df1<−na.omit(df1)
df1

Output

x1 x2
2 10 0
7 5 1
8 5 1
15 10 1
16 10 0
20 5 1

Example2

 Live Demo

y1<−sample(c(NaN,rnorm(5)),20,replace=TRUE)
y2<−sample(c(NaN,rnorm(2)),20,replace=TRUE)
df2<−data.frame(y1,y2)
df2

Output

y1 y2
1 0.71997269 NaN
2 0.31324492 NaN
3 0.71997269 −0.1903841
4 1.23101131 −0.1903841
5 0.09512564 −0.1903841
6 0.71997269 0.3998648
7 −0.14221014 −0.1903841
8 0.09512564 NaN
9 NaN NaN
10 1.23101131 0.3998648
11 −0.14221014 0.3998648
12 1.23101131 NaN
13 NaN 0.3998648
14 0.71997269 NaN
15 0.09512564 NaN
16 0.31324492 NaN
17 NaN NaN
18 0.09512564 0.3998648
19 1.23101131 0.3998648
20 0.71997269 −0.1903841

Removing rows with NaN from df2 −

Example

df2<−na.omit(df2)
df2

Output

y1 y2
3 0.71997269 −0.1903841
4 1.23101131 −0.1903841
5 0.09512564 −0.1903841
6 0.71997269 0.3998648
7 −0.14221014 −0.1903841
10 1.23101131 0.3998648
11 −0.14221014 0.3998648
18 0.09512564 0.3998648
19 1.23101131 0.3998648
20 0.71997269 −0.1903841