How to multiply vector values in sequence with columns of a data.table object in R?

R ProgrammingServer Side ProgrammingProgramming

To multiply vector values in sequence with data.table object columns in R, we can follow the below steps:−

  • First of all, create a data.table.

  • Then, create a vector.

  • After that, use t function for transpose and multiplication sign * to multiply vector values in sequence with data.table object columns.

Example 1

Create the data.table object

Let’s create a data.table object as shown below −

library(data.table)
var1<-sample(1:10,25,replace=TRUE)
var2<-sample(1:10,25,replace=TRUE)
var3<-sample(1:10,25,replace=TRUE)
DT1<-data.table(var1,var2,var3)
DT1

Output

On executing, the above script generates the below output(this output will vary on your system due to randomization) −

   var1 var2 var3
1:   9  8    4
2:   2  8    2
3:   7  8   10
4:   6  7   10
5:   2  5    9
6:   4  9    8
7:   8  1    6
8:   3  9    9
9:  10  2    4
10:  5  7    8
11:  2  5    7
12: 10  6    2
13:  9  3    9
14:  8  3   10
15:  4  3    9
16:  2  6    4
17:  4 10    4
18: 10  6    5
19:  2  9    5
20:  9  9    5
21:  7  8    1
22:  5  3    5
23:  6 10    4
24:  5  6   10
25:  2  1    5
   var1 var2 var3

Create the vector

Let’s create a vector as shown below −

v1<-c(10,10,10)
v1

Output

[1] 10 10 10

Multiply vector values in sequence with data.table object columns

Using t function for transpose and multiplication sign * to multiply v1 values in sequence with columns of data.table object DT1 as shown below −

library(data.table)
var1<-sample(1:10,25,replace=TRUE)
var2<-sample(1:10,25,replace=TRUE)
var3<-sample(1:10,25,replace=TRUE)
DT1<-data.table(var1,var2,var3)
v1<-c(10,10,10)
t(t(DT1)*v1)

Output

     var1 var2 var3
[1,]   90  80  40
[2,]   20  80  20
[3,]   70  80 100
[4,]   60  70 100
[5,]   20  50  90
[6,]   40  90  80
[7,]   80  10  60
[8,]   30  90  90
[9,]  100  20  40
[10,]  50  70  80
[11,]  20  50  70
[12,] 100  60  20
[13,]  90  30  90
[14,]  80  30 100
[15,]  40  30  90
[16,]  20  60  40
[17,]  40 100  40
[18,] 100  60  50
[19,]  20  90  50
[20,]  90  90  50
[21,]  70  80  10
[22,]  50  30  50
[23,]  60 100  40
[24,]  50  60 100
[25,]  20  10  50

Example 2

Create the data.table object

Let’s create a data.table object as shown below −

library(data.table)
x<-sample(1:50,25)
y<-sample(1:50,25)
z<-sample(1:50,25)
DT2<-data.table(x,y,z)
DT2

Output

On executing, the above script generates the below output(this output will vary on your system due to randomization) −

     x y  z
1:   3 33  8
2   35 25 43
3:   9 22 36
4:  17 26 27
5:  32  7 29
6:   4 23 13
7:  31  5 37
8:   1 20 41
9:  50 17 20
10: 37 30 25
11: 44 10  4
12: 43 42 42
13:  2 18  3
14: 33 37 22
15: 36 32 15
16: 49  2 26
17: 39 48 33
18: 23 24 11
19: 26 29 34
20: 48  8 14
21: 40 35  9
22: 22 36  1
23: 12 14 40
24: 19 12 10
25: 13  9  7
    x  y z

Create the vector

Let’s create a vector as shown below −

v2<-c(1,0.5,2)
v2

Output

[1] 1.0 0.5 2.0

Multiply vector values in sequence with data.table object columns 

Using t function for transpose and multiplication sign * to multiply v2 values in sequence with columns of data.table object DT2 as shown below −

library(data.table)
x<-sample(1:50,25)
y<-sample(1:50,25)
z<-sample(1:50,25)
DT2<-data.table(x,y,z)
v2<-c(1,0.5,2)
t(t(DT2)*v2)

Output

      x   y    z
[1,]   3 16.5 16
[2,]  35 12.5 86
[3,]   9 11.0 72
[4,]  17 13.0 54
[5,]  32  3.5 58
[6,]   4 11.5 26
[7,]  31  2.5 74
[8,]   1 10.0 82
[9,]  50  8.5 40
[10,] 37 15.0 50
[11,] 44  5.0  8
[12,] 43 21.0 84
[13,]  2  9.0  6
[14,] 33 18.5 44
[15,] 36 16.0 30
[16,] 49  1.0 52
[17,] 39 24.0 66
[18,] 23 12.0 22
[19,] 26 14.5 68
[20,] 48  4.0 28
[21,] 40 17.5 18
[22,] 22 18.0  2
[23,] 12  7.0 80
[24,] 19  6.0 20
[25,] 13  4.5 14
raja
Published on 12-Nov-2021 06:58:11
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