How to match anything except space and new line using Python regular expression?

Python's re module provides various tools for pattern matching using regular expressions (regex). With the help of regex, we can define flexible patterns that match or exclude particular characters or sequences. In this article, we will focus on how to match everything except spaces and newlines using regular expressions.

The following are the methods involved to match the regex pattern, except for space and new line −

• Using re.findall() Method
• Using re.split() Method
• Replace Spaces and Newlines with Empty String

Regular Expression Patterns for Non-Space Characters

Before diving into the methods, let's understand the key regex patterns used ?

• [^ \n]+ − Matches one or more characters that are NOT space or newline
• [ \n]+ − Matches one or more spaces or newlines
• \s+ − Matches any whitespace characters (spaces, tabs, newlines)

Using re.findall() Method

The re.findall() method extracts all parts of the text that don't contain a space or newline. We use the pattern r'[^ \n]+' to find all continuous sequences that exclude spaces and newlines ?

import re

text = "I find\nTutorialspoint useful"
matches = re.findall(r'[^ \n]+', text)
print("Original text:", repr(text))
print("Matched words:", matches)

The output of the above code is ?

Original text: 'I find\nTutorialspoint useful'
Matched words: ['I', 'find', 'Tutorialspoint', 'useful']

Using re.split() Method

The re.split() method splits a string into a list based on a specified pattern. Using r'[ \n]+' as the pattern, it splits wherever one or more spaces or newlines occur ?

import re

data = "Python is\ngreat for   regex"
parts = re.split(r'[ \n]+', data)
print("Original text:", repr(data))
print("Split result:", parts)

The output of the above code is ?

Original text: 'Python is\ngreat for   regex'
Split result: ['Python', 'is', 'great', 'for', 'regex']

Using re.sub() to Remove Spaces and Newlines

The re.sub() method replaces parts of a string that match a pattern with a replacement string. To remove all spaces and newlines, we replace them with an empty string ?

import re

text = "This\nhas some text \n with spaces"
clean = re.sub(r'[ \n]', '', text)
print("Original text:", repr(text))
print("After removing spaces/newlines:", clean)

The output of the above code is ?

Original text: 'This\nhas some text \n with spaces'
After removing spaces/newlines: Thishassometextwithspaces

Comparison of Methods

Advanced Example

Here's a practical example combining multiple approaches to process text data ?

import re

sample_text = "Hello\nWorld!  Python   regex\nis powerful."

# Method 1: Find all non-space words
words = re.findall(r'[^ \n]+', sample_text)
print("Words found:", words)

# Method 2: Split by whitespace
split_words = re.split(r'\s+', sample_text)
print("Split words:", split_words)

# Method 3: Remove all whitespace
no_spaces = re.sub(r'\s', '', sample_text)
print("No whitespace:", no_spaces)

The output of the above code is ?

Words found: ['Hello', 'World!', 'Python', 'regex', 'is', 'powerful.']
Split words: ['Hello', 'World!', 'Python', 'regex', 'is', 'powerful.']
No whitespace: HelloWorld!Pythonregexispowerful.

Conclusion

Use re.findall() with [^ \n]+ to extract words excluding spaces and newlines. Use re.split() to separate text into tokens, and re.sub() to remove unwanted whitespace characters entirely.