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How to extend Interfaces in Java
An interface contains variables and methods like a class but the methods in an interface are abstract by default unlike a class. An interface extends another interface like a class implements an interface in interface inheritance.
A program that demonstrates extending interfaces in Java is given as follows:
Example
interface A { void funcA(); } interface B extends A { void funcB(); } class C implements B { public void funcA() { System.out.println("This is funcA"); } public void funcB() { System.out.println("This is funcB"); } } public class Demo { public static void main(String args[]) { C obj = new C(); obj.funcA(); obj.funcB(); } }
Output
This is funcA This is funcB
Now let us understand the above program.
The interface A has an abstract method funcA(). The interface B extends the interface A and has an abstract method funcB(). The class C implements the interface B. A code snippet which demonstrates this is as follows:
interface A { void funcA(); } interface B extends A { void funcB(); } class C implements B { public void funcA() { System.out.println("This is funcA"); } public void funcB() { System.out.println("This is funcB"); } }
In the method main() in class Demo, an object obj of class C is created. Then the methods funcA() and funcB() are called. A code snippet which demonstrates this is as follows:
public class Demo { public static void main(String args[]) { C obj = new C(); obj.funcA(); obj.funcB(); } }
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