# How do you find continuous sub array whose sum is equal to a given number in Java?

To find continuous sub array whose sum is equal to a given number −

• Iterate through the array.
• At each element add the next n elements one by one, when the sum equals to the required value print the sub array.

## Example

import java.util.Arrays;
import java.util.Scanner;
public class sub_arrays {
public static void main(String args[]){
//Reading the array from the user
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the array that is to be created: ");
int size = sc.nextInt();
int[] myArray = new int[size];
System.out.println("Enter the elements of the array: ");
for(int i=0; i<size; i++){
myArray[i] = sc.nextInt();
}
System.out.println("Enter the required sum: ");
int reqSum = sc.nextInt();
System.out.println("The array created is: "+Arrays.toString(myArray));
System.out.println("sub arrays whose sum is: "+reqSum);
for(int i=0; i<myArray.length; i++){
int sum = 0;
for (int j=i; j<myArray.length; j++){
sum = sum + myArray[j];
if(sum == reqSum){
System.out.println(Arrays.toString(Arrays.copyOfRange(myArray, i, j+1)));
}
}
}
}
}

## Output

Enter the size of the array that is to be created:
10
Enter the elements of the array:
5
4
1
2
3
4
1
4
5
5
Enter the required sum:
10
The array created is: [5, 4, 1, 2, 3, 4, 1, 4, 5, 5]
sub arrays whose sum is: 10
[5, 4, 1]
[4, 1, 2, 3]
[1, 2, 3, 4]
[2, 3, 4, 1]
[1, 4, 5]
[5, 5]