How do you find continuous sub array whose sum is equal to a given number in Java?

Java 8 Object Oriented Programming Programming

To find continuous sub array whose sum is equal to a given number −

Iterate through the array.
At each element add the next n elements one by one, when the sum equals to the required value print the sub array.

Example

import java.util.Arrays;
import java.util.Scanner;
public class sub_arrays {
   public static void main(String args[]){
      //Reading the array from the user
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter the size of the array that is to be created: ");
      int size = sc.nextInt();
      int[] myArray = new int[size];
      System.out.println("Enter the elements of the array: ");
      for(int i=0; i<size; i++){
         myArray[i] = sc.nextInt();
      }
      //Reading the number
      System.out.println("Enter the required sum: ");
      int reqSum = sc.nextInt();
      System.out.println("The array created is: "+Arrays.toString(myArray));
      System.out.println("sub arrays whose sum is: "+reqSum);
      for(int i=0; i<myArray.length; i++){
         int sum = 0;
         for (int j=i; j<myArray.length; j++){
            sum = sum + myArray[j];
            if(sum == reqSum){
               System.out.println(Arrays.toString(Arrays.copyOfRange(myArray, i, j+1)));
            }
         }
      }
   }
}

Output

Enter the size of the array that is to be created:
10
Enter the elements of the array:
5
4
1
2
3
4
1
4
5
5
Enter the required sum:
10
The array created is: [5, 4, 1, 2, 3, 4, 1, 4, 5, 5]
sub arrays whose sum is: 10
[5, 4, 1]
[4, 1, 2, 3]
[1, 2, 3, 4]
[2, 3, 4, 1]
[1, 4, 5]
[5, 5]

Maruthi Krishna

Published on 02-Aug-2019 14:12:53

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