Grouping identical entries into subarrays - JavaScript

Let’s say, we have an array of numbers that have got identical entries. We are required to write a function that takes in the array and groups all the identical entries into one subarray and returns the new array thus formed.

For example: If the input array is −

const arr = [234, 65, 65, 2, 2, 234];

Then the output should be −

const output = [[234, 234], [65, 65], [2, 2]];

We will use a hashmap to keep a track of the elements already occurred and iterate over the array using a for loop.

Example

Following is the code −

const arr = [234, 65, 65, 2, 2, 234];
const groupArray = arr => {
   const map = {};
   const group = [];
   for(let i = 0; i < arr.length; i++){
      if(typeof map[arr[i]] === 'number'){
         group[map[arr[i]]].push(arr[i]);
      }else{
         //the push method returns the new length of array
         //and the index of newly pushed element is length-1
         map[arr[i]] = group.push([arr[i]])-1;
      }
   };
   return group;
}
console.log(groupArray(arr));

Output

This will produce the following output in console −

[ [ 234, 234 ], [ 65, 65 ], [ 2, 2 ] ]

AmitDiwan

Updated on 18-Sep-2020 12:47:12

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