Golang program to update the ith index node value, when index is at the nth position, i.e., out of index bound.

Example

Approach to solve this problem

Step 1 − Define a method that accepts the head of a linked list.

Step 2 − If head == nil, return the head.

Step 3 − Initialize the index as i := 0.

Step 4 − Iterate the given linked list from its head.

Step 5 − If index i matches with the given index (to be updated), then update that node.

Step 6 − Else, return head.

Example

 Live Demo

package main
import "fmt"
type Node struct {
   value int
   next *Node
}
func NewNode(value int, next *Node) *Node{
   var n Node
   n.value = value
   n.next = next
   return &n
}
func TraverseLinkedList(head *Node){
   temp := head
   for temp != nil {
      fmt.Printf("%d ", temp.value)
      temp = temp.next
   }
   fmt.Println()
}
func UpdateKthIndexNode(head *Node, index , data int) *Node{
   if head == nil{
      return head
   }
   i := 0
   temp := head
   for temp != nil{
      if i == index{
         temp.value = data
         break
      }
      i++
      temp = temp.next
   }
   return head
}
func main(){
   head := NewNode(30, NewNode(10, NewNode(40, NewNode(40, nil))))
   fmt.Printf("Input Linked list is: ")
   TraverseLinkedList(head)
   index := 10
   head = UpdateKthIndexNode(head, index, 15)
   fmt.Printf("Update %dth index node, Linked List is: ", index)
   TraverseLinkedList(head)
}

Output

Input Linked list is: 30 10 40 40
Update 10th index node, Linked List is: 30 10 40 40