Golang program to delete the ith index node, when index is the out of range in the linked list.

Example

Approach to solve this problem

Step 1 − Define a method that accepts the head of a linked list.

Step 2 − If head == nil, return the head.

Step 3 − When index == 0, then return head.next

Step 4 − Else, iterate the given linked list from its head.

Step 5 − If index i matches with the given index (to be deleted), then delete that node.next, break the loop.

Step 6 − Return, at the end of the loop.

Example

 Live Demo

package main
import "fmt"
type Node struct {
   value int
   next *Node
}
func NewNode(value int, next *Node) *Node{
   var n Node
   n.value = value
   n.next = next
   return &n
}
func TraverseLinkedList(head *Node){
   temp := head
   for temp != nil {
      fmt.Printf("%d ", temp.value)
      temp = temp.next
   }
   fmt.Println()
}
func DeleteKthIndexNode(head *Node, index int) *Node{
   if head == nil{
      return head
   }
   if index == 0{
      head = head.next
      return head
   }
   i := 1
   temp := head
   for temp != nil{
      if i == index{
         temp.next = temp.next.next
      }
      i++
      temp = temp.next
   }
   return head
}
func main(){
   head := NewNode(30, NewNode(10, NewNode(40, NewNode(40, nil))))
   fmt.Printf("Input Linked list is: ")
   TraverseLinkedList(head)
   index := 5
   head = DeleteKthIndexNode(head, index)
   fmt.Printf("After Deletion of %dth index node, Linked List is: ", index)
   TraverseLinkedList(head)
}

Output

Input Linked list is: 30 10 40 40
After Deletion of 5th index node, Linked List is: 30 10 40 40