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Generate an even squares between 1 to n using for loop in C Programming
Even square numbers are - 22, 42, 62, 82,………
= 4, 16, 36, 64, 100, ………
Algorithm
START Step 1: declare two variables a and n Step 2: read number n at runtime Step 3: use for loop to print square numbers For a=2; a*a<=n;a+=2 until the condition satisfy loop will continue and Print a*a STOP
Program 1
#include<stdio.h> int main(){ int a,n; printf("enter a number for n:"); scanf("%d",&n); for(a=2;a*a<=n;a+=2) //print even squares that are present in between 1 and n{ printf("%d
",a*a); } return 0; }
Output
enter a number for n:200 4 16 36 64 100 144 196
Program 2
Following is the program to find even cubes between 1 to n −
#include<stdio.h> int main(){ int a,n; printf("enter a number for n:"); scanf("%d",&n); for(a=2;a*a*a<=n;a+=2){ printf("%d
",a*a*a); } return 0; }
Output
enter a number for n:300 8 64 216
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