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Generate a Hermite_e series with given complex roots in Python
To generate a Hermite_e series with given complex roots, use the hermite_e.hermefromroots() method in Python Numpy. The method returns a 1-D array of coefficients. If all roots are real then out is a real array, if some of the roots are complex, then out is complex even if all the coefficients in the result are real. The parameter roots are the sequence containing the roots.
Steps
At first, import the required library −
from numpy.polynomial mport hermite_e as H
Generate a Hermite_e series with given complex roots −
j = complex(0,1)
print("Result...\n",H.hermefromroots((-j, j)))Get the datatype −
print("\nType...\n",H.hermefromroots((-j, j)).dtype)Get the shape −
print("\nShape...\n",H.hermefromroots((-j, j)).shape)Create an arrayExample
from numpy.polynomial import hermite_e as H
j = complex(0,1)
print("Result...\n",H.hermefromroots((-j, j)))
# Get the datatype
print("\nType...\n",H.hermefromroots((-j, j)).dtype)
# Get the shape
print("\nShape...\n",H.hermefromroots((-j, j)).shape)Output
Result... [2.+0.j 0.+0.j 1.+0.j] Type... complex128 Shape... (3,)
Updated on: 11-Mar-2022
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