# Fizz Buzz in Python

Suppose we have a number n. We have to display a string representation of all numbers from 1 to n, but there are some constraints.

• If the number is divisible by 3, write Fizz instead of the number
• If the number is divisible by 5, write Buzz instead of the number
• If the number is divisible by 3 and 5 both, write FizzBuzz instead of the number

To solve this, we will follow these steps −

• For all number from 1 to n,
• if a number is divisible by 3 and 5 both, print “FizzBuzz”
• otherwise when the number is divisible by 3, print “Fizz”
• otherwise when the number is divisible by 5, print “Buzz”
• otherwise, write the number as a string

## Example

Let us see the following implementation to get a better understanding −

Live Demo

class Solution(object):
def fizzBuzz(self, n):
"""
:type n: int
:rtype: List[str]
"""
result = []
for i in range(1,n+1):
if i% 3== 0 and i%5==0:
result.append("FizzBuzz")
elif i %3==0:
result.append("Fizz")
elif i% 5 == 0:
result.append("Buzz")
else:
result.append(str(i))
return result
ob1 = Solution()
print(ob1.fizzBuzz(30))

## Input

30

## Output

["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz",
"13","14","FizzBuzz","16","17","Fizz","19","Buzz","Fizz","22","23",
"Fizz","Buzz","26","Fizz","28","29","FizzBuzz"]

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