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First occurrence of True number in Python
In this article we are required to find the first occurring non-zero number in a given list of numbers.
With enumerate and next
We sue enumerate to get the list of all the elements and then apply the next function to get the first non zero element.
Example
listA = [0,0,13,4,17]
# Given list
print("Given list:\n " ,listA)
# using enumerate
res = next((i for i, j in enumerate(listA) if j), None)
# printing result
print("The first non zero number is at: \n",res)Output
Running the above code gives us the following result −
Given list: [0, 0, 13, 4, 17] The first non zero number is at: 2
With next and filter
The next and filter conditions are applied to the elements of the list along with lambda expression with a condition not equal to zero.
Example
listA = [0,0,13,4,17]
# Given list
print("Given list:\n " ,listA)
# using next,filetr and lambda
res = listA.index(next(filter(lambda i: i != 0, listA)))
# printing result
print("The first non zero number is at: \n",res)Output
Running the above code gives us the following result −
Given list: [0, 0, 13, 4, 17] The first non zero number is at: 2
Updated on: 04-Jun-2020
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