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Finding smallest number that satisfies some conditions in JavaScript
We are required to write a JavaScript function that takes in a number as the first argument, say n, and an array of numbers as the second argument. The function should return the smallest n digit number which is a multiple of all the elements specified in the array.
If there exist no such n digit element then we should return the smallest such element.
For example: If the array is −
const arr = [12, 4, 5, 10, 9]
For both n = 2 and n = 3,
Output
The output should be −
180
Therefore, let’s write the code for this function −
Example
The code for this will be −
const arr = [12, 4, 5, 10, 9]
const num1 = 2;
const num2 = 3;
const allDivides = (arr, num) => arr.every(el => num % el === 0);
const smallestMultiple = (arr, num) => {
let smallestN = Math.pow(10, (num - 1));
while(!allDivides(arr, smallestN)){
smallestN++;
};
return smallestN;
};
console.log(smallestMultiple(arr, num1));
console.log(smallestMultiple(arr, num2));Output
The output in the console will be −
180 180
Updated on: 17-Oct-2020
162 Views
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