Finding a pair that is divisible by some number in JavaScript

JavascriptWeb DevelopmentFront End Technology

We are required to write a JavaScript function that takes in an array of Numbers as the first argument, let's call it arr and a single number as the second argument, let's call it num.

The function should find all such pairs from the array where −

arr[i] + arr[j] = num, and
i < j

For example −

If the input array and the number is −

const arr = [1, 2, 3, 4, 5, 6];
const num = 4;

Then the output should be −

const output = [
   [1, 3], [2, 6], [3, 5]
];

Example

The code for this will be −

 Live Demo

const arr = [1, 2, 3, 4, 5, 6];
const num = 4;
const divisibleSumPairs = (arr = [], num) => {
   const res = [];
   const { length } = arr;
   for(let i = 0; i < length; i++){
      for(let j = i + 1; j < length; j++){
         const sum = arr[i] + arr[j];
         if(sum % num === 0){
            res.push([arr[i], arr[j]]);
         }
      }
   }
   return res;
};
console.log(divisibleSumPairs(arr, num));

Output

And the output in the console will be −

[ [ 1, 3 ], [ 2, 6 ], [ 3, 5 ] ]
raja
Published on 24-Feb-2021 05:42:40
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