# Finding Log1p() of the Given Number in Golang

The math.Log1p() function in Golang is used to calculate the natural logarithm of (1 + x) for a given value x. The Log1p() function is useful when x is very small, as the usual formula to calculate the natural logarithm may cause a loss in precision. This function is also known as log(1 + x), where x is a floating-point number.

In this article, we will discuss the Log1p() function and its usage in Golang, along with an example.

## Syntax

The syntax for using the math.Log1p() function is as follows −

func Log1p(x float64) float64


The function takes one argument, which is the value of x, a floating-point number, for which we need to calculate the natural logarithm.

## Return Value

The math.Log1p() function returns the natural logarithm of (1 + x) for the given value of x.

## Example

Let's see an example that uses the math.Log1p() function to calculate the natural logarithm of (1 + x) for a given value of x.

package main

import (
"fmt"
"math"
)

func main() {
x := 0.5
result := math.Log1p(x)

fmt.Printf("Natural logarithm of (1 + %.2f) is: %.2f\n", x, result)
}


## Output

Natural logarithm of (1 + 0.50) is: 0.41


In this example, we have imported the "math" package and used the Log1p() function to calculate the natural logarithm of (1 + x) for a given value of x = 0.5. The result is printed using the Printf() function of the "fmt" package.

Here's another example to demonstrate the usage of math.Log1p() −

## Example

package main

import (
"fmt"
"math"
)

func main() {
x := 3.0
result := math.Log1p(x)
fmt.Printf("log(1+%f) = %f", x, result)
}


## Output

log(1+3.000000) = 1.386294


In this example, we pass the value 3.0 as the argument to math.Log1p(). The function calculates the natural logarithm of 1+x and returns the result. In this case, the result is 1.386294.

## Conclusion

The math.Log1p() function is a useful function in Golang when we need to calculate the natural logarithm of (1 + x) for a given value of x. This function is useful when the value of x is very small, and the usual formula to calculate the natural logarithm may cause a loss in precision.

Updated on: 12-Apr-2023

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